Get Directory List From Server

How can I get directory list from the server?

With this code you can list all files in a given directory:

Code:

import java.io.File;
 
public class ListFiles 
{
 
 public static void main(String[] args) 
{
 
  // Directory path here
  String path = "."; 
 
  String files;
  File folder = new File(path);
  File[] listOfFiles = folder.listFiles(); 
 
  for (int i = 0; i < listOfFiles.length; i++) 
  {
 
   if (listOfFiles[i].isFile()) 
   {
   files = listOfFiles[i].getName();
   System.out.println(files);
      }
  }
}
}
 

If you want to list only .txt files for example, Use this:

Code:

import java.io.File;
 
public class ListFiles 
{
 
 public static void main(String[] args) 
{
 
  // Directory path here
  String path = "."; 
 
  String files;
  File folder = new File(path);
  File[] listOfFiles = folder.listFiles(); 
 
  for (int i = 0; i < listOfFiles.length; i++) 
  {
 
   if (listOfFiles[i].isFile()) 
   {
   files = listOfFiles[i].getName();
       if (files.endsWith(".txt") || files.endsWith(".TXT"))
       {
          System.out.println(files);
        }
     }
  }
}
}

Note:
You can modify the .txt or .TXT to be whatever file extension you wish. 
 

Alternative to test for files with a certain ending:

Code:

MyFilter implements FileFilter
{
     public boolean accepts(File pathname)
     {
          if (pathname.endswith(".txt") || pathname.endswith(".TXT"))
          {
               return true;
          }
          return false;
     }
}
 

Code:

import java.io.File;
 
public class ListFiles 
{
 
 public static void main(String[] args) 
{
 
  // Directory path here
  String path = "."; 
 
  String files;
  File folder = new File(path);
  File[] listOfFiles = folder.listFiles(new MyFilter()); 
 
  for (int i = 0; i < listOfFiles.length; i++) 
  {
          System.out.println(listOfFiles[i].getName());
  }
}
}

Technically, this code will display folders named hello.txt, or this is a directory.txt, but I think it's fairly safe to assume that most people won't name their directories this way. 

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